a-4[b-4(c-x)]=5

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Solution for a-4[b-4(c-x)]=5 equation:


Simplifying
a + -4[b + -4(c + -1x)] = 5
a + -4[b + (c * -4 + -1x * -4)] = 5
a + -4[b + (-4c + 4x)] = 5
a + [b * -4 + -4c * -4 + 4x * -4] = 5
a + [-4b + 16c + -16x] = 5

Solving
a + -4b + 16c + -16x = 5

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '4b' to each side of the equation.
a + -4b + 16c + 4b + -16x = 5 + 4b

Reorder the terms:
a + -4b + 4b + 16c + -16x = 5 + 4b

Combine like terms: -4b + 4b = 0
a + 0 + 16c + -16x = 5 + 4b
a + 16c + -16x = 5 + 4b

Add '-16c' to each side of the equation.
a + 16c + -16c + -16x = 5 + 4b + -16c

Combine like terms: 16c + -16c = 0
a + 0 + -16x = 5 + 4b + -16c
a + -16x = 5 + 4b + -16c

Add '16x' to each side of the equation.
a + -16x + 16x = 5 + 4b + -16c + 16x

Combine like terms: -16x + 16x = 0
a + 0 = 5 + 4b + -16c + 16x
a = 5 + 4b + -16c + 16x

Simplifying
a = 5 + 4b + -16c + 16x

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